In classical kinetic theory, consider a molecule traveling a total path length $L$. The effective volume it sweeps out is $\pi d^2 L$, where $d$ is the molecular diameter. If the number density of the gas is $n$, then the number of molecules within this volume is $\pi n d^2 L$, meaning the number of collisions experienced is:
\[N = \pi n d^2 L\]The mean free path $\Lambda$ between two collisions is then:
\[\Lambda = \frac{L}{N} = \frac{L}{\pi n d^2 L} = \frac{1}{n \sigma}\]where $\sigma = \pi d^2$ is the collision cross-section.
Substituting the ideal gas relation $n = \frac{p}{k_B T}$ gives:
\[\Lambda = \frac{k_B T}{p \sigma}\]To calculate the heat flux from a single molecule, assume its internal energy is $\varepsilon$, and its velocity component in the $x$ direction is $v_x$. Then the energy transfer per unit time is approximately:
\[q_x = \frac{1}{2} v_x \left[\varepsilon(x - \Lambda_x) - \varepsilon(x + \Lambda_x)\right]\]Expanding using a Taylor series and neglecting higher-order terms:
\[q_x \approx -v_x \Lambda_x \frac{\mathrm{d} \varepsilon}{\mathrm{d}x} \approx -(\cos^2\theta) v \Lambda \frac{\mathrm{d} \varepsilon}{\mathrm{d}x}\]Integrating over all directions (assuming isotropy), the total heat flux is:
\[q_x = -\frac{1}{2\pi} v \Lambda \frac{\mathrm{d} \varepsilon}{\mathrm{d}x} \left[\int_0^{2\pi} \mathrm{d}\varphi \int_0^{\pi/2} \cos^2\theta \sin\theta \, \mathrm{d}\theta \right] \frac{\mathrm{d} \varepsilon}{\mathrm{d}T} \frac{\mathrm{d}T}{\mathrm{d}x}\]Which simplifies to:
\[q_x \approx -\frac{1}{3} C v \Lambda \frac{\mathrm{d}T}{\mathrm{d}x}\]The resulting thermal conductivity is:
\[\lambda = \frac{1}{3} C v \Lambda\]This shows that thermal conductivity is proportional to specific heat $C$, molecular speed $v$, and mean free path $\Lambda$.
In dielectrics such as insulators or semiconductors, heat is carried by phonons, the quantized vibrations of the crystal lattice. Each phonon has energy $\hbar \omega$, where $\omega$ is the vibrational frequency.
Phonon thermal conductivity is similarly given by:
\[\lambda_{ph} = \frac{1}{3} C_{ph} v_s \Lambda_{\Sigma}\]where:
Main phonon scattering mechanisms include:
According to Matthiessen’s rule, the total inverse mean free path is the sum of the individual contributions:
\[\Lambda_{\Sigma}^{-1} = \Lambda_{ph}^{-1} + \Lambda_{imp}^{-1} + \Lambda_{b}^{-1}\]In metals, heat is mainly carried by free electrons. The thermal conductivity of the electron gas is:
\[\lambda_{e} = \frac{1}{3} C_{e} v_F \Lambda_{e}\]where:
Again using Matthiessen’s rule:
\[\frac{1}{\Lambda_e} = \frac{1}{\Lambda_{ph}} + \frac{1}{\Lambda_d} + \frac{1}{\Lambda_b}\]At the microscopic level, heat transport is described by particle distribution functions. In equilibrium, these are:
When far from equilibrium, the distribution becomes $f(\vec{r}, \vec{p}, t)$ and evolves according to the Boltzmann transport equation:
\[\frac{\partial f}{\partial t} + \vec v \cdot \nabla_{\vec r} f + \vec F \cdot \nabla_{\vec p} f = \left(\frac{\partial f}{\partial t}\right)_\text{st}\]where the right-hand collision term $\left(\partial f / \partial t\right)_{\text{st}}$ describes how the system relaxes toward equilibrium.
At the macroscopic level, classical Fourier’s law governs steady-state heat conduction:
\[\vec q = -\lambda \nabla T\]Substituting into energy conservation gives the heat diffusion equation:
\[\rho C_p \frac{\partial T}{\partial t} = -\nabla \cdot \vec q\]Which becomes:
\[\rho C_p \frac{\partial T}{\partial t} = \lambda \nabla^2 T \quad \Rightarrow \quad \frac{\partial T}{\partial t} = a \nabla^2 T\]Here, $a = \frac{\lambda}{\rho C_p}$ is the thermal diffusivity, describing how temperature disturbances propagate in the medium.